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Append Argument

提出詳細

type AppendArgument<Fn extends (...args: any[]) => any, A> = Fn extends (...args: infer Args) => infer Return
  ? (...args: [...Args, A]) => Return
  : never

提出日時	2023-08-11 09:11:56
問題	Append Argument
ユーザー	tekihei2317
ステータス	Accepted

テストケース

import type { Equal, Expect } from '@type-challenges/utils'

type Case1 = AppendArgument<(a: number, b: string) => number, boolean>
type Result1 = (a: number, b: string, x: boolean) => number

type Case2 = AppendArgument<() => void, undefined>
type Result2 = (x: undefined) => void

type cases = [
  Expect<Equal<Case1, Result1>>,
  Expect<Equal<Case2, Result2>>,
]